Tuesday, January 20, 2009

Electrical Formulas

Posted on/at 7:00 PM by Sparky

For your Information.


Electrical Conversion Formulas for three-phase AC power:

  • E represents volts
  • I represents amps
  • Eff represents motor efficiency
  • PF represents power factor
  • If PF is not known, assume 0.85
  • If Eff is not known, assume 0.90

·To find Amps when Horsepower is known:
Amps = (hp × 746) ÷ (1.73 × E × Eff × PF)

·To find Amps when Kilowatts are known:
Amps = (kW × 1000) ÷ (1.73 × E × PF)

·To find Amps when Kilovolt Amperes are known:
Amps = (kVA × 1000) ÷ (1.73 × E)

·To find Kilowatts when Amps, Volts and Power Factor are known:
kW = (I × E × 1.73 × PF) ÷ 1000

·To find Kilovolt Amperes when Amps and Volts are known:
kVA = (I × E × 1.73) ÷ 1000

·To find Kilowatts when Kilovolt Amperes and Power Factor are known:
kW = (kVA × PF)

·To find Kilowatts when Horsepower and Eff are known:
kW = hp × 0.746 ÷ Eff

Electrical Conversion Formulas for single-phase AC power:

  • E represents volts
  • I represents amps
  • PF represents power factor
  • If PF is not known, assume 0.85
  • If Eff is not known, assume 0.90

·To find Amps when Horsepower is known:
Amps = (hp × 746) ÷ (E × Eff × PF)

·To find Amps when Kilowatts are known:
Amps = (kW × 1000) ÷ (E × PF)

·To find Amps when Kilovolt Amperes are known:
Amps = (kVA × 1000) ÷ (E)

·To find Kilowatts when Amps, Volts and Power Factor are known:
kW = (I × E × PF) ÷ 1000

·To find Kilovolt Amperes when Amps and Volts are known:
kVA = (I × E) ÷ 1000

·To find Kilowatts when Kilovolt Amperes and Power Factor are known:
kW = (kVA × PF)

·To find Kilowatts when Horsepower and Eff are known:
kW = hp × 0.746 ÷ Eff


OHM's law

4 comments:

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L. Venkata Subramaniam said...

wow very nice. I read all this when I was doing my engineering way back in the late 80s. good to be reminded of them now.